I have been working on a project which involves an Arduino communicating serially with an LCD display device. Through a lot of trial and error, I finally figured out that when you want to send a HEX-encoded byte from the Arduino, you need to use the Serial.write() command rather than the Serial.print() command. The Serial.print() command works find when you are sending an ASCII byte but it will not work when you try to send a HEX byte. The right and wrong ways are below:
//Serial.print('U'); <----right (ASCII)
//Serial.write('U'); <----also fine (ASCII)
//Serial.print(0x55); <----WRONG! (HEX)
//Serial.write(0x55); <----right (HEX)
LINKS:
Similar problem and solution:
http://www.arduino.cc/playground/Learning/SparkFunSerLCD
You can also pass in a second argument to specify the base.
ReplyDeleteSerial.print(0x55, HEX);
http://arduino.cc/en/Serial/Print
That is not right, it will send 55 in ASCI or 0x35 0x35 in HEX.
DeleteI can confirm this.
Deletewhat about multiple bytes?
ReplyDeleteSerial.write(0x55,0x99,0x20,0x60); ????
Thank you so much for this. Straightforward and useful!
ReplyDeleteI have the same problem....How to sent multiple bytes. I need to send 0x55 0x01 0x00 over the serial port. How is th=his best done?
ReplyDeleteOne way is to create a variable at the beginning of your program such as:
Deleteuint8_t my_serial_bytes[3]={0x55, 0x01, 0x00};
...then call it like:
Serial.write(my_serial_bytes,sizeof(my_serial_bytes));
This is especially helpful when you are using the same serial command frequently in your program. Good luck!
Can the same unsigned integer above be read from a port : Serial.read(my_serial_bytes, size of(my_serial_bytes)); ?
DeleteI appreciate people do the work.
DeleteAhh finally :)
ReplyDeleteThank you so much.
i wrote code a couple years ago that worked, now with the update it doesn't work and i had to change the code to be more ... versatile.
Right: LCD
ReplyDeleteRight: LC-Display
Wrong: LCD Display
Hi nick! Thank you so much for this blog!!
ReplyDeleteI have a question.
I am sending a hex packet from one Arduino to another Arduino using two max 485s (so using rs485 protocol).
If I use a uint8_t array of hex numbers to serial.write to one arduino, how can I read it in the other arduino. I guess my question is, how do you use the serial.read to read in a uint8_t pair by pair?
Hi did you figure this out? I have the same problem, I am trying to send a bunch of hex codes using RS485. I have a RS485 shield for arduino and the hex codes I need to send are of the format 0xFF 0x01 0x05 0xAA etc. I'm using hardware serial. Unfortunately I am not getting back anything from the device.
DeleteHi, did you try using nick.weil answer?
Delete""One way is to create a variable at the beginning of your program such as:
uint8_t my_serial_bytes[3]={0x55, 0x01, 0x00};
...then call it like:
Serial.write(my_serial_bytes,sizeof(my_serial_bytes));""
or do find another way??
Hello i need this too plz help how to READ HEX from serial
Deletehttp://arduino.cc/en/Tutorial/ASCIITable
ReplyDeleteHi guys, I have issue in the following code, I want to send the hex numbers serially and expected to recieve the same type of data serially but on serial monitor i got garbage value even my baudrate are same.. Here is my code,,
ReplyDeleteconst byte numChars = 88;
char receivedChars[numChars]; // an array to store the received data
boolean newData = false;
void setup() {
Serial.begin(9600);
Serial.println("");
}
void loop()
{
uint8_t message[] = {0xA5, 0x0D, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x0d };
Serial.write(message, sizeof(message));
recvWithEndMarker();
showNewData();
}
void recvWithEndMarker() {
static byte ndx = 0;
char endMarker = '\n';
char rc;
while (Serial.available() > 0 && newData == false)
{
rc = Serial.read();
if (rc != endMarker) {
receivedChars[ndx] = rc;
ndx++;
if (ndx >= numChars) {
ndx = numChars - 1;
}
}
else {
receivedChars[ndx] = '\0'; // terminate the string
ndx = 0;
newData = true;
}
}
}
void showNewData() {
if (newData == true) {
Serial.print("data ");
Serial.println(receivedChars);
newData = false;
}
}
any kind of hint and comment will be helpful
As far as I can see, we can easily find the solution when dealing with this. Sending the correct data would not be a problem any longer.
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